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Greeley [361]
3 years ago
6

Suppose you bought a 6 percent coupon bond one year ago for $920. The bond sells for $940 today.

Mathematics
1 answer:
velikii [3]3 years ago
7 0

Answer:

1. $80

2. 8.69%

3. 5.53%

Step-by-step explanation:

The computation is shown below:

1. Total dollar return

= Face value × interest rate + (Sale value - purchase value)

= $1,000 × $60 + ($940 - $920)

= $60 + $20

= $80

2. Total nominal rate of return equal to

= {Face value × interest rate + (Sale value - purchase value)} ÷ {Purchase value} × 100

= {$1,000 × $60 + ($940 - $920)} ÷ {$920} × 100

= ($60 + $20) ÷ ($920) × 100

= 8.69%

3. Total real rate of return is

= (1 + Nominal rate of return) ÷ (1 + Inflation rate) × 100

= (1 + 8.70%) ÷ (1 + 0.03) × 100

= 5.53%

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Step-by-step explanation:

4 0
3 years ago
Solve for f. 2+1.25f=10-2.75f2+1.25f=10−2.75f
Ne4ueva [31]
We have to solve for f:
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6 0
3 years ago
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

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(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

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\Delta f = 3

Both sequences are arithmetic.

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2 years ago
The Tire on franks bike moves 75 inches in one rotation. How many rotations will the tire have made after frank rides 50 feet
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Answer:

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Step-by-step explanation:

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<u>= -43</u>

4 0
2 years ago
Read 2 more answers
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