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4 years ago

Identify the phrase that cannot be described by the same absolute value as the other three. Explain your reasoning.

Mathematics

1 answer:

r-ruslan [8.4K]4 years ago

6 0

The answer would probably be 18 degrees below normal because the absolute values of the rest are 8 not 18 which is the absolute value of 18 degrees below normal.

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The slope of a line parallel to -x + y = 12 equals what?

Viktor [21]

1. parallel lines have same slope

7 0

3 years ago

Here are two offers for batteries.

trapecia [35]

OFFER A is cheaper.

Step-by-step explanation:

Given,

OFFER A

Pack of 5

£2.75

Pay for 3 packs get 1 free

And

OFFER A

Pack of 5

£2.75

Pay for 3 packs get 1 free

To find which offer is cheaper.

For OFFER A

For 4 Packets he needs to pay £2.75

He needs to buy 40 batteries.

He needs to buy 40÷(4×5) = 2 packets.

Total cost = £2.75 ×2 = £5.5

For OFFER B

For 4 Packets he needs to pay £2.52

He needs to buy 40 batteries.

He needs to buy 10 packets.

After discount he has to pay = £2.52 -(£2.52 × $\frac{1}{3}$ ) = £1.68

Total cost = £1.68×10 = £16.8

Hence,

OFFER A is cheaper.

7 0

3 years ago

Euclid Park is shaped like a square, with side length s, and has an area of 121 square kilometers. This equation shows the area

SpyIntel [72]

The answer is 11 because 121/4 (4=sides) =11

6 0

3 years ago

HELP Question below in the photo linked

lora16 [44]

Answer:

D. x = 10, m<TRS = 60°

Step-by-step explanation:

m<QRS = 122° (given)

m<QRT = (7x - 8)° (given)

m<TRS = (6x)° (given)

m<QRT + m<TRS = m<QRS (angle addition postulate)

(7x - 8)° + (6x)° = 122° (substitution)

Solve for x

7x - 8 + 6x = 122

Add like terms

13x - 8 = 122

13x = 122 + 8

13x = 130

x = 130/13

x = 10

✔️m<TRS = (6x)°

Plug in the value of x

m<TRS = (6*10)° = 60°

6 0

3 years ago

Does anyone know this answer??

Aleonysh [2.5K]

For this case we have the following equation:

$(2x + 3) ^ 2 + 8 (2x + 3) + 11 = 0$

Let $u = 2x + 3$

We have:

$u ^ 2 + 8u + 11 = 0$

By definition, given an equation of the form $ax ^ 2 + bx + c = 0$

The quadratic formula, to find the solution can be written as:

$x = \frac{-b+/-\sqrt{b ^ 2-4 (a) (c)} }{2(a)}$

In this case we have:

$a = 1\\b = 8\\c = 11$

Substituting in the quadratic formula we have:

See attached image

Answer:

Option B

8 0

3 years ago

Read 2 more answers