Answer:
y= -2x-5
Step-by-step explanation:
First find the gradient of the first line
m=
m=
m=1/2
From this we can find the gradient of the perpendicular line, or the normal.
m1 × m2 = -1
Replace m1 with 1/2
1/2 × m2 = -1
m2= -2
Substitute values into
y-y1=m (x-x1)
y-3=-2 (x+4)
y-3=-2x -8
y=-2x-5
Answer:
y=5
Step-by-step explanation:
Get rid of the parenthesis by multiplying
2y=6+4
Add
2y=10
Divide
y=5
Answer:
(x + y - 2xy)*(x + y + 2xy)
Step-by-step explanation:
x^2-4x^2y^2+y^2+2*x*y
=x^2 + 2xy + y^2 - (2xy)^2
=(x + y)^2 - (2xy)^2
=(x + y - 2xy)*(x + y + 2xy)
Step-by-step explanation:
RS bisects PQ at T. PQ bisects RS at T.
<u>prove</u>: Triangle PTS congruent Triangle QTR
<h3>Statements..............................Reasons</h3>
(1) RS bisects PQ at T.................(1) Given
(2) PQ bisects RS at T.................(2) Given
(3) angle PST ≅ angle QRT........(3) supplements of congruent angles
(4) TS ≅ TR......................(4) Converse of Base Angles Theorem
(5) angle PTS ≅ angle QTR.........(5) Subtraction Property of Equality
(6) Triangle PTS ≅ Triangle QTR...(6) Angle side angle
Hope it's help you..... ^_^❤️
Check the picture below.
so we know S is the midpoint of PQ, and T is the midpoint of QR, thus
so, what's the distance from S to T?
![\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &S&(~ -6 &,& 7~) % (c,d) &T&(~ -3 &,& 4~) \end{array}\\\\\\ % distance value d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ST=\sqrt{[-3-(-6)]^2+[4-7]^2}\implies ST=\sqrt{(-3+6)^2+(4-7)^2} \\\\\\ ST=\sqrt{3^2+(-3)^2}\implies ST=\sqrt{18}\implies ST=\sqrt{9\cdot 2} \\\\\\ ST=\sqrt{3^2\cdot 2}\implies ST=3\sqrt{2}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%26%26x_2%26%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%26S%26%28~%20-6%20%26%2C%26%207~%29%20%0A%25%20%20%28c%2Cd%29%0A%26T%26%28~%20-3%20%26%2C%26%204~%29%0A%5Cend%7Barray%7D%5C%5C%5C%5C%5C%5C%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AST%3D%5Csqrt%7B%5B-3-%28-6%29%5D%5E2%2B%5B4-7%5D%5E2%7D%5Cimplies%20ST%3D%5Csqrt%7B%28-3%2B6%29%5E2%2B%284-7%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0AST%3D%5Csqrt%7B3%5E2%2B%28-3%29%5E2%7D%5Cimplies%20ST%3D%5Csqrt%7B18%7D%5Cimplies%20ST%3D%5Csqrt%7B9%5Ccdot%202%7D%0A%5C%5C%5C%5C%5C%5C%0AST%3D%5Csqrt%7B3%5E2%5Ccdot%202%7D%5Cimplies%20ST%3D3%5Csqrt%7B2%7D)
