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sesenic [268]
3 years ago
13

What do you know about the signs of two intergers whose product (a) positive and (b) negative?

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0
( + ) ( - ) = ( - )
steposvetlana [31]3 years ago
5 0
A. Their signs are the same.
b. one is negative, the other is positive
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Equation, find y when x=-3.<br><br> y = -x + 5<br><br> When x = -3, y =
Step2247 [10]
I think y = 8. Since x = -3 then the equation would be y = -1(-3) +5. -1 times -3 equals 3. So now the equation is y = 3 +5. That would give you 8.
7 0
3 years ago
Which equations are correct? Select each correct answer.
netineya [11]
The answer to the question is the second and the fourth equations
6 0
3 years ago
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Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

+5)=−(10p+5)

Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

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3 years ago
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A server brings 9 bread sticks to a table with 4 people. How many bread sticks each persons gets ?
AURORKA [14]

Answer:

2 1/4

Step-by-step explanation:

Each person gets 2 1/4 bread sticks.

9÷4= 2 1/4

3 0
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Answer:

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Step-by-step explanation:

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