The correct answer is y= 0.513(1.833)^x
Explain
We will use the equation on this form
Y=ab^x
Let’s us plug in the coordinates of first point
(X, y) , ( 9, 120)
We will have
Y=ab^x
120= ab^9
Our equation for a will be
Ab^9 = 120
ab ^9 / b^9 = 120/ b^9
a = 120/ b^9
So will have
Y= 120/ b^9 • b^x
Then we will plug in coordinates for the second point
( x,y) = ( 10, 220)
We will have
Y= 120/b^9 • b^x
220 = 120/b^9 • b^10-9
220= 120b
Divide both side by 120
B= 11/6
B= 1.833333 = 1.833
Let’s plug in the value b=11/6 to our equation for a
A= 120/b^9
A= 120/ 11/6^9
A= 120/11^9/6^9
A=120 • 6^9 / 11^9
= 0.51285 which equal to 0.513
So therefore the answer is
Y= 0.513(1.833)^x
I hope this help you
:D
<u>Answer:
</u>
The population of a city has decreased by 38% since it was last measured. If the current population is 27,900 .Previous population of city was 45000.
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Solution:
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Given that current population of city is 27900.
Also, population of a city has decreased by 38% since it was last measured.
Let assume that population of city when it was last measured = x
Decreased of 38% means x-38% of x . we can write this as,
So current population is 
Equating above expression to the given value of current population, we get
x=45000
Hence previous population of city was 45000.
Answer:
93
Step-by-step explanation:
15 x 5 = 75 + 18 = 93
Answer:
The probability that the person will not be a senior
P(E⁻) = 1 - P(E)
= 
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given A high school club has 10 members who are seniors and 8 members who are juniors
n(S) = 10 + 8 = 18
If a member is randomly selected to be the club president
Let 'E' be the event that the person will be a senior
The probability that the person will be a senior
The probability that the person will not be a senior
P(E⁻) = 1 - P(E)
=
1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25
2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
180-154=2f=26
angle f=13
QPR=13
3. so we assume that BG is straight so it is 180
we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
5x=55
x=11
CQD=2x=22
EQF=3x=33
4. we know that x=x and the whole is 360 so
x+x+x+x+71+71+71+71=360=4x+284=360
4x=76
x=19
8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
99=3x
CQG=99
9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20 20*4=80 20*5=100 4:5 =80:100
a. 80 and 100
b. you should be able to do this
10. so on a line is 180
a. 3:4:5 3+4+5=12 180/12=15
3*15=45 4*15=60 5*15=75
3:4:5 =45:60:75
the angles are 45 60 75
b. you should be able to do this from my work
