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3 years ago

How do I solve this?

Mathematics

1 answer:

Ghella [55]3 years ago

8 0

The product of the two segments from the two chords are equal.

4(4+5)=(x-2)(x-2+x+4) or 36=(x-2)(2x+2) or x^2-x-20=0 or (x-5)(x+4)=0

So x=5.

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2(1 - 5k) = 2k + 38<br> HURRY I NEED THIS ANSWER FAST

alexgriva [62]

Answer:

hope this helps

Step-by-step explanation:

8 0

3 years ago

What is 1.513 written as a percent

Arada [10]

Remember this, DOOP

This stands for decimal, two zeros, then percent.

So, what you do is, since 1.513 is a decimal, you move the decimal two places to the right. You get 151.3
Therefore, 1.513 is 151.3%

6 0

3 years ago

Read 2 more answers

The angles of a triangle are 80º, 2x + 2º, and 5xº. What is the value of x?

Lady bird [3.3K]

If you add 5x to 2x+2 you will get 7x+2. You would set this equation equal to 80, so it would be 7x+2=80. When you solve this you will get 11.1428571429, which can be rounded to 11, 11.1, or 11.14, whichever you prefer.

3 0

3 years ago

How to solve 9x 4 2/5 in words

Natalija [7]

Answer:

39.6

Thirty nine point six

Step-by-step explanation:

9 x 4 2/5

9 x 22/5

198/5 = 39.6

Thirty nine point six

3 0

3 years ago

[Quick Answer Needed] Which of the following shows the extraneous solution to the logarithmic equation?

Nitella [24]

Answer:

Step-by-step explanation:

Given the logarithmic equation

$\log_4x+\log_4(x-3)=\log_4(-7x+21)$

First, notice that

$x>0\\ \\x-3>0\Rightarrow x>3\\ \\-7x+21>0\Rightarrow 7x$

So, there is no possible solutions, all possible solutions will be extraneous.

Solve the equation:

$\log_4x+\log_4(x-3)=\log_4x(x-3),$

then

$\log_4x(x-3)=\log_4(-7x+21)\\ \\x(x-3)=-7x+21\\ \\x^2-3x+7x-21=0\\ \\x^2+4x-21=0\\ \\D=4^2-4\cdot 1\cdot (-21)=16+84=100\\ \\x_{1,2}=\dfrac{-4\pm 10}{2}=-7,\ 3$

Hence, $x=3$ and $x=-7$ are extraneous solutions

6 0

3 years ago