3 years ago

Use the above figure to answer the question. What's the angle between the tangents at T in the figure?

1 answer:

3 0

Please give a picture so I can see

You might be interested in

Blababa [14]

-4/10+5/10
=5/10-4/10
=1/10

5 0

2 years ago

serious [3.7K]

Tangent always meets radius at 90° angle.

Angle ABC = 90° so Pythagoras' theorem applies.

r² + 4² = (r+2)²
r² + 16 = r² + 4r + 4
12 = 4r
r = 3

5 0

3 years ago

CaHeK987 [17]

$x^{\frac{1}{2}} = \sqrt[2]{x}$ and $3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}$ so

$3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x} = \frac{\sqrt{x}}{\sqrt{3}}$

and you rationalize denominator by multiplying numerator and denominatr by $\sqrt{3}$ so that gives--

$\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}$

Your answer is $\frac{\sqrt{3x}}{3}$

5 0

2 years ago

shusha [124]

The answer is 3 9/10 c

5 0

3 years ago

matrenka [14]

Answer:

∠3 = 107°

Step-by-step explanation:

Similar to the other question, ∠3 and ∠4 are supplementary and add up to 180 degrees as they make up the entirety of a straight line.

∠4 is 73°, so ∠3 has to be 107°.

4 0

2 years ago