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OverLord2011 [107]
3 years ago
7

Can someone help me with this please??!!

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

2.4 ft

Step-by-step explanation:

h = v/ pie r^2

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What is the remainder of f(x)=x^4-2x^3-27x^2-9x+18 when divided by binomial x+4
givi [52]

Answer:

The remainder will be 6.

Step-by-step explanation:

We have the function:

f(x)=x^4-2x^3-27x^2-9x+18

And we want to find the remainder after it is divided by the binomial:

x+4

We can use the Polynomial Remainder Theorem. According to the PRT, if we have a polynomial P(x) being divided by a binomial in the form (<em>x</em> - <em>a</em>), then the remainder will be given by P(a).

Here, our divisor is (<em>x</em> + 4). We can rewrite this as (<em>x</em> - (-4)).

Therefore, <em>a</em> = -4.

Then according to the PRT, the remainder will be:

f(-4)=(-4)^4-2(-4)^3-27(-4)^2-9(-4)+18=6

The remainder will be 6.

4 0
2 years ago
Select three ratios that are equivalent to 8:5.
zalisa [80]

Answer:

A,D,E IS THE RATIOS EUQIVALENT TO8:5

3 0
2 years ago
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Write the expression<br> a2b3c2d in expanded<br> form.
Zanzabum

Answer:

a*2+b*2+c*2+d

Step-by-step explanation:

If i's meant to be Pythagorean theorem, a*a+b*b=c*c

8 0
3 years ago
NEED THE ANSWER ASAP PLEASE
ValentinkaMS [17]

Answer:

X = -2

Step-by-step explanation:

Vertical lines go up and down.  That means the x value is constant and the y value changes.  We have an x value of -2

X = -2

8 0
2 years ago
Which of the following expression expressions is equivalent to cos3x/sinxcosx?
77julia77 [94]
Correct Option:
Option B

Solution:
The given expression is:

\frac{cos(3x)}{sin(x)cos(x)}

cos(3x) can be written as cos(2x +x). Expanding it, we get:

cos(3x) = cos(2x+x) \\  \\ &#10;cos(3x) =cos(2x)sin(x)-sin(2x)cos(x)

Using this value of cos(3x) in given equation, we get:

\frac{cos(3x)}{sin(x)cos(x)} \\  \\ &#10;= \frac{cos(2x)sin(x)-sin(2x)cos(x)}{sin(x)cos(x)} \\  \\ &#10;= \frac{cos(2x)sin(x)}{sin(x)cos(x)}- \frac{sin(2x)cos(x)}{sin(x)cos(x)}  \\  \\ &#10;= \frac{cos(2x)}{cos(x)} - \frac{sin(2x)}{sin(x)} \\  \\ &#10;=sec(x)cos(2x)-csc(x)sin(2x)
8 0
3 years ago
Read 2 more answers
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