“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
2/5, a, and b is the answer
Hello hello I hope am not feeling good about yoyy
4x-3y=-32
x=-2y-13
4x-3y=-32
4(-2y-13)-3y=-32
-8y-52-3y=-32
-11y-52=-32
-11y=20
11y=-20
y=-20/11
x=-2y-13
x=-2(20/11)-13
x=-40/11-13
x=-13 and 40/11
Answer:
numbers:letters
5:4 (numbers:letters form)
Step-by-step explanation:
There are 5 numbers in the password and 4 letters
Hopefully this helps :)
