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Alinara [238K]
3 years ago
15

Use substitution to solve the system. 4x-3y=−32 x=−2y-13

Mathematics
1 answer:
mixer [17]3 years ago
6 0
4x-3y=-32
x=-2y-13

4x-3y=-32
4(-2y-13)-3y=-32
-8y-52-3y=-32
-11y-52=-32
-11y=20
11y=-20
y=-20/11

x=-2y-13
x=-2(20/11)-13
x=-40/11-13
x=-13 and 40/11
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lilavasa [31]
7+2(3+2)
7+2(5)
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5 0
3 years ago
Read 2 more answers
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
2 years ago
PLEASE HELP NEED THIS TO PASS
yaroslaw [1]

The solutions to f(x) = 64 is x = 7 and x = –7.

Solution:

Given data:

$f(x)=x^{2}+15 – – – – (1)

f(x)=64 – – – – (2)

To find the solutions to f(x) = 64.

Equate equation (1) and (2), we get

x^2+15=64

Subtract 15 from both sides of the equation.

x^2+15-15=64-15

x^2=49

x^2=7^2

Taking square root on both sides of the equation, we get

x = ±7

The solutions to f(x) = 64 is x = 7 and x = –7.

5 0
3 years ago
0.33333333333333333333333333333333333333333333333 simplified at a fraction
USPshnik [31]

Answer:

\frac{1}{3}

Step-by-step explanation:

Your original number to convert is 0.333333. Let's slide the decimal point in this number to the right 1 place(s) (the same number of digits in the number 3).

If we do this, we'll get a 3.333333 (slide the decimal in the 0.333333 right 1 places, you'll get 3.333333).

So what? Well now, we have two numbers with the same repeating decimal parts, 3.333333 and 0.333333.

Now let's just work a little algebra into all of this. Let's call your original number x. And in this case, x = 0.333333. The number with the decimal point slid over can be called 10x, because 10x = 3.333333

10x = 3.33333

-x = 0.333333\frac{10x = 3.33333  -x = 0.333333}{9x = 3}

---------------------------------------------------------------------------------------------

Now, solving 9x=3 for x by dividing both sides of it by 9, we'll get that x=3/9. And this is your answer.

How is this your answer? Well remember that above, x was originally set equal to 0.333333 via x = 0.333333, and now we have that x is also equal to 3/9, so that means 0.333333 = 3/9..and there's 0.333333 written as a fraction.

-------------------------------------------------------------------------------------------

<u>Simplify 3/9 into the lowest terms:</u>

\frac{1}{3}

4 0
3 years ago
Help me pls. Pls do this step by step. I will give he brainliest to the person who does it step by step.
Zanzabum

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Step-by-step explanation:

x^3 +y^3 - (x + y)^3​

Expand the expression

x^2 + y^3 - (x^3 + 3x^2y + 3xy^2 +y3)

Remove the parentheses

x^2 +y^3 -x^3 -3x^2y -3xy^2 - y^3

Remove the opposites

Answer:

x^2 - x^3 - 3x^2y - 3xy^2

Hope this Helps!

3 0
2 years ago
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