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4 years ago

I dont really want to fail this test again. Please give it your best try

Mathematics

2 answers:

castortr0y [4]4 years ago

8 0

Answer:

A) One set of data has more variation than the other.

Step-by-step explanation:

did the test

o-na [289]4 years ago

7 0

Answer:

Step-by-step explanation:

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Justin uses 4 right angles to draw a polygon. How many different polygons can he make?

Vitek1552 [10]

He can make an infinite number of different polygons,
as long as each one has more than 3 sides.

If the polygon has four sides, then it's always a parallelogram
and a rectangle, and it might also be a square.

3 0

3 years ago

Read 2 more answers

What error did Tracy make? She used AG = 2EG, but the correct statement is 2AG = GE. She found that x = 4, but the correct value

azamat

Answer:

C. She used GF = 2BG, but the correct statement is BG = 2GF.

Step-by-step explanation:

credits to the other person!

8 0

3 years ago

Read 2 more answers

X^2-8x-36=0<br> solve by completing the square <br> ANSWER ASAP

larisa86 [58]

Answer:

hope it helps

7 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago

Find, as a ratio, the scale of a map given as 2cm to 1km. If two towns are 23.4cm apart on the map, what is the actual distance

Rina8888 [55]

Answer:

The actual distance is 11.7km

Step-by-step explanation:

2cm = 1km

1cm = 0.5km

23.4cm = ?

23.4 × 0.5 = 11.7km

(Correct me if i am wrong)

8 0

3 years ago