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Naily [24]
3 years ago
8

Sandy had 10 dollars in her collection. she gave 3 to her younger sister. her parents were so impressed that they quadrupled (le

ft multiplied by 4) her remaining dolls.
Mathematics
2 answers:
Natali5045456 [20]3 years ago
3 0
She had $100 and she gave $3 to her sister so $10-$3=$7 and her parent quadrupled her remaining dollars which was $7 so $7x4=$28 the answer is $28
Free_Kalibri [48]3 years ago
3 0

Answer:

Her remaining dollars are 28.

Step-by-step explanation:

Consider the provided information.

Sandy has 10 dollars in her collection.

She gave 3 to her younger sister.

Remaining dollars are:

$10 - $3 = $7

Her parents were so impressed that they quadrupled (left multiplied by 4).

So $7 × 4 = $28

The expression can be 7 × 4 = x.

Hence she left with $28.

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ch4aika [34]

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Answer:

  A) J(-3, 1), ...

Step-by-step explanation:

All of the answer choices list point J' first, so it is convenient to use that as an example.

Point J on the given graph has coordinates (x, y) = (3, 2). The x-coordinate is 3 because the point is 3 units to the right of the y-axis.

The problem statement tells you to translate this point 6 units to the left. When you move it 6 units left, it will move left 3 units to the y-axis, then left 3 more units to have an x-coordinate of 3 -6 = -3. That is, each unit of movement to the left subtracts 1 from the x-coordinate. The x-coordinate of J is 3, so the final point J' will have an x-coordinate of 3 - 6 = -3.

At this point, you have enough information to make the correct answer selection. Only one answer choice has the x-coordinate of J' as -3.

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The other coordinates are translated using similar logic. The y-coordinate of J is 2. Translating it down 1 unit subtracts 1 from the y-coordinate to make it be 2 -1 = 1. Then the coordinates of J' are (-3, 1).

We write the translation rule as ...

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This means the coordinates of each translated point have 6 subtracted from the original x-coordinate, and 1 subtracted from the original y-coordinate. The other coordinates of the figure are ...

  I(2, 4) ⇒ I'(2 -6, 4 -1) = I'(-4, 3)

  H(5, 5) ⇒ H'(5 -6, 5 -1) = H'(-1, 4)

  G(4, 1) ⇒ G'(4 -6, 1 -1) = G'(-2, 0)

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Step-by-step explanation:

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