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stiv31 [10]
3 years ago
7

WILL GIVE BRAINLIEST!! A ramp is 12 inches high and rises with a 17° angle. How long is the base?

Mathematics
1 answer:
Blababa [14]3 years ago
6 0
X=3.93 in. 
hope this helps you ♥
You might be interested in
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\
\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
Point c d and g lie on plane x. Point e and f lie on plane y. Which statements are true
emmasim [6.3K]

The true statements are: 3, 4 and 5

Step-by-step explanation:

search it up

5 0
3 years ago
Read 2 more answers
Y=x^2+2x+1 find the vertex
Bess [88]
I'm going to put this into vertex form, which is y=a(x-h)^2+k

To do this, you use completing the square. Start by subtracting 1 from each side

-1+y=x^2+2x

Then, divide b (2) by 2 and square it. Add that number to each side. (normally when you complete the square, you take out the gcf of the right side of the equation before you do this. Then, you would multiply (b/2)^2 by the gcf before adding it to the left side. Since there is no gcf, we do not have to worry about this)

2/2=1
1^2=1
-1+1+y=x^2+2x+1

Next, simplify the left side and factor the right side.

y=(x+1)^2

This is vertex form. a=1, h=-1, and k=0

The vertex is (h,k) so it is (-1,0)

hope this helps!
7 0
4 years ago
Read 2 more answers
Hiiii, can someone plz help me?
bonufazy [111]
I believe the answer is C.
6 0
3 years ago
Express answer in exact form.
Fiesta28 [93]
A chord and a radius form an equilateral triangle.
The area of the larger segment is:
A = 5/6 r² π + r²√3/2 = 5/6 · 64 · 3.14 + 32 · 1.73 =
= 167.47 + 55.36 = 222.83 in²
3 0
3 years ago
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