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frosja888 [35]
3 years ago
7

On a maps coordinate grid, Walt City is located at (-1,-3) and Koshville is located at (4,9). How long is a trains route as the

train travels along a straight line from Walt city to Koshville
Mathematics
1 answer:
Valentin [98]3 years ago
3 0
5 blocks away from W to K.
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Is (1, 3) a solution to this system of equations?
andrezito [222]

Answer:

no

because it doesn't work with the first equation

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ANYONE KNOWS THAT ANSWER FOR THIS PLEAS EHELP ME ASAP
Tasya [4]

Answer:

triangular prism

Step-by-step explanation:

Shape 1 attached is a triangular prism it has the same name and same net but is not identical as its slightly longer. The top side has 5 edges and its base has 4 edges

Has the same Faces: 5

Has the same Edges: 9

Has the same Vertices: 6

Shape 2 attached, is called a square based pyramid

It differs as its top side has 4 edges and its base has 4 edges where the base is the only common side and slope as the other one.

Faces: 5

Edges: 8

Vertices: 5

3 0
3 years ago
( -8.7 ) • ( -10 ) = ?
Ber [7]

Answer:

87

Step-by-step explanation:

A negative times a negative always equals a positive, and 10 times anything is just moving the decimal point to the right once, so 8.7 becomes 87.0

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3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
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A lawn in the shape of a trapezoid has an area of 1,800 square meters. The length of one base is 50 meters, and the length of th
Alona [7]

9514 1404 393

Answer:

  40 m

Step-by-step explanation:

The area is given by the formula ...

  A = 1/2(b1 +b2)h

Using the given values, we can find h to be ...

  1800 = 1/2(50 +40)h

  3600 = 90h . . . . . . . . . multiply by 2

  40 = h . . . . . . . . . . . divide by 90

The width of the lawn is 40 meters.

6 0
3 years ago
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