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3 years ago

10

A(n) ____ is a client, server, or other device that can communicate over a network and is identified by a unique number, known a

s its network address.

Computers and Technology

1 answer:

Elden [556K]3 years ago

7 0

Answer:

The answer is "node".

Explanation:

The network address is known as a logical or physical address, which defines a networking module/device from a network. It is an allocated numerical number, to every device requiring access to the list or is a member of it.

In network communication, it uses the nodes for store data, and there address, these addresses are described by the unique numbers.
These node stores data packets, which stores encrypted data.

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Which type of network is the internet? choose the answer

Alex Ar [27]

Answer:

WAN or wide area network

Explanation:

The Internet is the most basic example of a WAN. It is connecting all computers together around the world.

5 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

Which is a common problem caused by the widespread use of computers?

Andru [333]

Hacking would be a widespread problem.

8 0

4 years ago

Matts has finished running some security automation scripts on three newly deployed Linux servers. After applying intrusion dete

gizmo_the_mogwai [7]

Answer: CPU

Explanation:

The management dashboard refers to the tool that's used in the presentation of the vital k management KPIs in a single place, which is efficiently managed in order to make faster and better decisions.

Based on the information given, after the application of intrusion detection, virus, and malware protection on the Linux images, he will notices an increase in CPU on his server management dashboard.

Therefore, the correct option is C.

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3 years ago

You have a chart that shows 100 data points and you've circled the highest value. Which of the following are you using?

cricket20 [7]

The Rudolph Rule states that simple ways you can make information stand out and guide or satisfy your audience to important details and highlight important information in your presentation

so i conclude option D is correct for above statement

hope it helps

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3 years ago

Read 2 more answers