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4 years ago

PLEASE HELPP

Mathematics

2 answers:

Oksana_A [137]4 years ago

7 0

Answer:

the solution is the point $(2,4)$

Step-by-step explanation:

we have

$13x-6y=2$ ------> equation A

$3x-4y=-10$ ------> equation B

we know that

The solution of the system of equations is the intersection point both graphs

Using a graphing tool

The intersection point is the point $(2,4)$

see the attached figure

therefore

the solution is the point $(2,4)$

Vera_Pavlovna [14]4 years ago

5 0

Https://photomath.net/s/ELAPA
this link should help you answer your question

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Grant earns $5 for each magazine he sells.Write an equation in two variables showing the relationship between the number pf maga

slega [8]

Answer:

$A=5m$

Grant will make $60 from selling 12 magazines.

Step-by-step explanation:

Let m represent number of magazine sold and A represent amount of money earned.

We have been given that Grant earns $5 for each magazine he sells. So amount earned from m magazines would be 5 times m that is $5m$ dollars.

Now, we will equate total amount earned by Grant with A as:

$A=5m$

Therefore, our required equation would be $A=5m$ .

To find the amount earned by Grant by selling 12 magazines, we will substitute $m=12$ in our equation as:

$A=5(12)$

$A=60$

Therefore, Grant will make $60 from selling 12 magazines.

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4 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

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nika2105 [10]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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