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Arturiano [62]
3 years ago
15

Find the percent of change: 30 inches to 24 inches

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0
It changes every 6 inches
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Is this increasing, decreasing, or constant? -4
bixtya [17]
I think -4 would be decreasing.
5 0
3 years ago
A trapezoid has the following dimensions:
mestny [16]
Area =
sum of the length of the parallel sides
multiplied by the distance between them
divided by two


area = \frac{(3+5) times by 3 }{2}

area = \frac{8 times by 3}{2}

area = \frac{24}{2}

area = 12

add the units:

area = 12 inches^{2}
4 0
3 years ago
Add the following fractions. Write the sum in simplest form. (the choices are written as mixed numbers): 3/4 + 4/5
Natali [406]

Answer:31/20

Step-by-step explanation:

5 0
3 years ago
What is the value of the rational expression x^2-2x-3/4x^2-12 when x = 3?
kotykmax [81]

Answer:

b

Step-by-step explanation:

Given

\frac{x^2-2x-3}{4x^2-12}

Substitute x = 3 into the expression

= \frac{3^2-2(3)-3}{4(3)^2-12}

= \frac{9-6-3}{36-12}

= \frac{0}{24} = 0 → b

6 0
3 years ago
A company offers a raffle whose grand prize is a $35,000 new car. Additional prizes are a $1,100 television and $600 computer. T
anastassius [24]

Answer:

-$ 10.13

Step-by-step explanation:

Given,

The cost price of each ticket = $ 22,

So, the value of each ticket other than price ticket = - $ 22, ( negative sign shows loss,i.e. if we don't get the price we will have the loss of $ 22 )

Now, there are 3 tickets in which first is of $35,000 price, second is of $1,100 and third is of $ 600,

So, the value of first ticket = 35000 - 22 = $ 34978,

Value of second ticket = 1100 - 22 = $ 1078,

Value of third ticket = 600 - 22 = $ 578,

Also,

\text{Probability}=\frac{\text{Favourable outcome}}{\text{Total outcome}}

Hence, by the above information we can make a table for the given situation,

Number           2997               1                    1                     1        

Price               -$ 22               $ 34978        $ 1078           $ 578

Probability       2997/3000      1/3000         1/3000           1/3000

Therefore, the expected value of a ticket

=-22\times \frac{2997}{3000}+34978\times \frac{1}{3000}+578\times \frac{1}{3000}

=-$10.126

≈ - $ 10.13

5 0
3 years ago
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