Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?
<span>These triangles are impossible:
a triangle with sides of 3 inches, 4 inches, and 8 inches
(the longest side is greater than the sum of the other 2 sides)
an obtuse equilateral triangle
(all angles in an </span><span>equilateral triangle are acute)
</span>
<span>a triangle with two right angles
The angles of ALL triangles must sum exactly to 180 degrees. Two right angles sum to 180 degrees so the third angle would have to be zero degrees.
</span>
Add 6x and 4x to make 10x
then it's 10x + 2 < 14
then subtract the 2 from the 14
10x< 12
divide 10
x< 12/ 10
simplify
x< 6/5 or 1 1/5
32/72
because you keep 8/3 and the multiplication sign and then flip the 24/4 to 4/24 and then solve for that and then the simplified answer would be 4/9
Answer:
im sorry man teach me how to do this as best as u can