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Step2247 [10]
3 years ago
8

#6) PLEASE HELP WITH QUESTION! MARKING BRAINLIEST.

Mathematics
2 answers:
uysha [10]3 years ago
8 0
Should be C) limit does not exist
there is a point at x = 2 because the dot is there! without that dot, there would be a limit at 2, 6 coming from left, and 2, -3 coming from the right
scoundrel [369]3 years ago
7 0
-3 and 6 please give brainliest
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PLEASE HELP ME :)))Micheal is making scale drawings of rectangular rooms using a scale of 1in to 1 1/2 feet
Aleksandr-060686 [28]

Answer:

a) 256 ft^2 No

b) 150 ft^2 Yes

c) 300 ft^2 NO

d) 192 ft^2 Yes

w=8.5 in

l=11 in

A=w•l

A=8.5•11=93.5 in^2

Scale:

1in:1.5 ft

1in^2:2.25 ft^2

1in ^2. 2.25ft^2

93.5 in^2. Xft^2

X=2.25•93.5

X=210.375

Step-by-step explanation:

3 0
3 years ago
If 9y=9 and x=-15,what is y when x=21
olga55 [171]

Welcome to Brainly!

This problem is odd in that no information is given regarding the relationship, if any, between x and y, and (more importantly) x can't have both values -15 and 21.  Please go back and ensure that you have copied down this problem precisely as it was given you.


6 0
3 years ago
The lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy length
lesya [120]

Answer:

68.268%.

Step-by-step explanation:

Let \mu be the mean pregnancy length.

The given standard deviation, \sigma=7 days

The z-score:

z=\frac{x-\mu}{\sigma}

where x is any pregnancy length.

The range of x within 7 days of the mean pregnancy length is

\mu-7

z-score for this range is:

\frac{\mu-7-\mu}{\sigma}

\Rightarrow -1

So, the area on the normally distributed curve for the above range of z-score will give the expected percentage of birds to occur within 7 days of the mean pregnancy length.

Now, from the z-score table:

The area from z = -\infty to z=1 is 0.84134

and the area from z = -\infty to z=-1 is 0.15866.

So, the area for -1<z<1

=0.84134 - 0.15866

=0.68268

Hence, the percentage of births would be expected to occur within 7 days of the mean pregnancy length=68.268%.

7 0
3 years ago
A cheetah attends the speed of 110 km per hour but the fastest human Sprinter goes a hundred meters in 9.58 seconds. How many ti
poizon [28]

Answer:

73.27 km/hr

Step-by-step explanation:

The fastest human sprinter sprints 100 metres in 9.58 seconds. Thus, speed of sprinter is;

V_sprinter = 100/9.8

V_sprinter = 10.204 m/s

Now, from conversion, 1 m/s = 3.6 km/hr

Then, 10.204 m/s = (10.204 × 3.6)/1 = 36.73 km/h

The cheetah sprints 110 km/hr

Thus, the cheetah is faster by: 110 - 36.73 = 73.27 km/hr

5 0
3 years ago
What is the slope of the line in the graph?<br> 5452-
algol13

Answer:

(0,5452) that every thing

4 0
3 years ago
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