Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Answer:
the final option: -2x to the power of nine
Step-by-step explanation:
honestly i'm in 20 minutes of sleep so i really hope you don't need the explanation
-the tired korean
<span>Faster maid DATA:
time = x hr/job ; rate = 1/x job/jhr
Slower maid DATA:
time = 3x hr/job ; rate = 1/3x job/hr
Together DATA:
time = 3 hr/job ; rate = 1/3 job/hr
Equation:
rate + rate = together rate
1/x + 1/3x = 1/3
Multiply thru by 3x to get:
3 + 1 = x
x = 4 hrs (time for the faster maid to do the job)</span>
Answer:
200,000
Step-by-step explanation:
3 odd integers have a property that they average up to the middle large one. Let's say we have 3, 5, and 7. 3 is 2 less than 5 and 7 is 2 more than 5. so when you add them it equals 2 times 5.
After we know that, the sum of 3 odd integers is just 3 times the middle number. ex. 3+5+7 = 3 times 5 = 15
Then we know the some number times three = 225. we find out that the middle number is 75, so the other two are 73 and 77
