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Mice21 [21]
3 years ago
15

The sum of two consecutive odd integers equals 12. What are they?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer:

x = 5

The two consecutive odd integers are: 5, 7

And...checking

sum = 12

Step-by-step explanation:

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Calculate the total surface area of the pyramid. Show your work!
Vinil7 [7]

Answer: 22.44

Step-by-step explanation:

Base × Height /2 → (3 × 2.24)/2

3.36 · 4 = 13.44

13.44 + 3²

22.44

7 0
3 years ago
What is the probability of you picking a weekend day from the days of the week?
svet-max [94.6K]

Answer:

3/7

Step-by-step explanation:

its 3/7 because there are 3 weekend days and there are 7 days in total in one week, so out of the week there is 3 weekend days.

i hope this helps :)

6 0
3 years ago
How many pairs of while number have a sum of 110
Vesnalui [34]
There is a lot of numbers
3 0
3 years ago
Read 2 more answers
A textbook store sold a combined total of 290 math and history textbooks in a week. The number of math textbooks sold was 64 mor
11Alexandr11 [23.1K]

Answer:

113

Step-by-step explanation:

290 - 64 = 226

226 ÷ 2 = 113

4 0
2 years ago
If
arlik [135]

Given:

In a right angle triangle θ is an acute angle and \tan\theta =\dfrac{3}{5}.

To find:

The value of \cos \theta.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

We have,

\tan\theta =\dfrac{3}{5}

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

Hypotenuse=\sqrt{Perpendicular^2+base^2}

Hypotenuse=\sqrt{(3x)^2+(5x)^2}

Hypotenuse=\sqrt{9x^2+25x^2}

Hypotenuse=\sqrt{34x^2}

Hypotenuse=x\sqrt{34}

In a right angle triangle,

\cos \theta=\dfrac{Base}{Hypotenuse}

\cos \theta=\dfrac{5x}{x\sqrt{34}}

\cos \theta=\dfrac{5}{\sqrt{34}}

Therefore, the value of \cos \theta is \dfrac{5}{\sqrt{34}}.

8 0
3 years ago
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