3 years ago

The sum of two consecutive odd integers equals 12. What are they?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

8 0

Answer:

x = 5

The two consecutive odd integers are: 5, 7

And...checking

sum = 12

Step-by-step explanation:

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Find the 17th term in the sequence for which a1 = 10 and d = -3.

yKpoI14uk [10]

Answer:

d. -38

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is as follows:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

$a_{n} = a_{1} + (n-1)*d$

In this question:

$a_{1} = 10, d = -3$

17th term:

$a_{17} = a_{1} + (17-1)*d = 10 + 16*(-3) = -38$

So the correct answer is:

d. -38

6 0

3 years ago

Helppp plsssss!!show your work.<br>Thanks

gregori [183]

You are basically just adding, so combine like terms.

3x^2 + 5x^2 = 8x^2

6x - 2x = 4x

4 - 8 = -4

So the answer is D.

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3 years ago

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M=7n make n the subject

Olin [163]

We divide both sides by 7 which makes n alone. Which is n=m/7.

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3 years ago

Factor completely: (3a+6)^2

zvonat [6]

(3(a+2))^2 factored

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3 years ago

(4 - 10) - ( 8 ÷ ( -2))

NeTakaya

The answer would be -2

(4-10)-(8 ÷(-2))

(-6)-(-4)

-6+4

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3 years ago

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