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JulsSmile [24]
3 years ago
7

Can someone show me the work for this?

Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
We are given the equation or function <span> y = sqrt (2x + 1). The derivative of the equation is expressed as 

</span><span>1. dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
</span>when x = 4 and dx/dt =3
dy/dt = 0.5 *2 *3*(2*4 + 1)^-0.5 
dy/dt = 1

2. <span>dy/dt = 0.5 *2 *(2x + 1)^-0.5 dx/dt
</span><span> If dy/dt = 5, find dx/dt when x = 12.
</span><span>    5= 0.5 *2 (2*12 + 1)^-0.5 dx/dt
   dx/dt = 1 </span>
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\sf\:Given\:expression: log(\dfrac{x^2 y^3}{z} )

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2 years ago
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