Question

The distance d of a particle moving in a straight line is given by d(t) = 2t^3 + 5t – 2, where t is given in seconds and d is measured in meters. Find the velocity of the particle for t = 7 seconds.
152 m/s
47 m/s
733 m/s
299 m/s

Answer 1

Answer: 299 m/s

Step-by-step explanation:

The first step is to take the first derivative of the equation given. This will give us the equation for velocity which we will then substitute the 7 in for t.

To derive the equation you multiply the coefficient by the power of the variable, then subtract one from the variable.

v(t) = 6t^2 + 5

Now input 7 in for t to find the velocity.

v(7) = 6(7)^2 + 5

v(7) = 299 m/s