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Mademuasel [1]
3 years ago
6

the coordinates of a triangle are given as A(3,2), B(-4,1),C(-3,-2). what are the coordinates of the image after the triangle is

reflected in the line y=x?​
Mathematics
2 answers:
Verizon [17]3 years ago
7 0

A reflection is a transformation where the mirror image of a figure is shown directly opposite its line of reflection.

To find an image that has been reflected across the line y = x, switch the x- and y-coordinates.

Therefore, the rule for reflecting an image across the line y = x can be described as (x, y) → (y, x).

Now, apply rule to coordinates ABC:

A': (2, 3)

B': (1, -4)

C': (-2, -3)

vesna_86 [32]3 years ago
6 0

Answer:

got it right on odyssey

A'(2,3)

B'(1,-4)

C'(-2,-3)

Step-by-step explanation:

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Step-by-step explanation:

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zlopas [31]

Answer:

Part 1) 324\pi\ units^{2} ------> 7,776\pi\ units^{3}

Part 2) 36\pi\ units^{2} ------> 288\pi\ units^{3}

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Part 4) 144\pi\ units^{2} ------> 2,304\pi\ units^{3}

Step-by-step explanation:

we know that

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Part 1) we have

A=324\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

324\pi=\pi r^{2}

Solve for r

r^{2}=324

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For r=18\ units

substitute

V=\frac{4}{3}\pi (18)^{3}

V=7,776\pi\ units^{3}

Part 2) we have

A=36\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

36\pi=\pi r^{2}

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r^{2}=36

r=6\ units

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V=\frac{4}{3}\pi r^{3}

For r=6\ units

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V=\frac{4}{3}\pi (6)^{3}

V=288\pi\ units^{3}

Part 3) we have

A=81\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

81\pi=\pi r^{2}

Solve for r

r^{2}=81

r=9\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=9\ units

substitute

V=\frac{4}{3}\pi (9)^{3}

V=972\pi\ units^{3}

Part 4) we have

A=144\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

144\pi=\pi r^{2}

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r^{2}=144

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The volume of the sphere is

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For r=12\ units

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V=\frac{4}{3}\pi (12)^{3}

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Answer:

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kobusy [5.1K]
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Solution
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