Ask question

Ask question

All categories

3 years ago

6

the coordinates of a triangle are given as A(3,2), B(-4,1),C(-3,-2). what are the coordinates of the image after the triangle is

reflected in the line y=x?

2 answers:

Verizon [17]3 years ago

7 0

A reflection is a transformation where the mirror image of a figure is shown directly opposite its line of reflection.

To find an image that has been reflected across the line y = x, switch the x- and y-coordinates.

Therefore, the rule for reflecting an image across the line y = x can be described as (x, y) → (y, x).

Now, apply rule to coordinates ABC:

A': (2, 3)

B': (1, -4)

C': (-2, -3)

vesna_86 [32]3 years ago

6 0

Answer:

got it right on odyssey

A'(2,3)

B'(1,-4)

C'(-2,-3)

Step-by-step explanation:

You might be interested in

HELP ASAP!!! 5. The following two triangles are similar. Find x.<br> х<br> 6<br> 56<br> 48<br> 5

ivanzaharov [21]

Answer:

x = 7

Step-by-step explanation:

The yellow triangle to the green triangle, is dilated to 1/8 of its original size. So 56/8 = 7

So x = 7

8 0

3 years ago

Read 2 more answers

Write the expression: 3 divided by the sum of x and 9. A) 3 + 9 x B) x 3 + 9 C) x + 9 3 D) 3 x + 9

yuradex [85]

Yes that is the answer

8 0

3 years ago

Read 2 more answers

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers

Abcd is a kite. Find the value of X <br> X+20 <br> X+10

Artemon [7]

Answer:

Abcd is a kite. Find the value of X

X+20

X+10

Step-by-step explanation:

5 0

3 years ago

Is the system of equations consistent and independent, consistent and dependent, or inconsistent?

kobusy [5.1K]

Answer: (x,y)=(-22/69 , 2/23)

Y=6x+2
3x+12y=6x+2
Simplify the expression

-6x+y=2
-3x+12y=2
Multiply both sides of the equation by

-6x+y=2
6x-24y=-4
eliminate at least one variable by adding the equation

-23y=-2
Divide both sides

y=2/23
Substitute the value of y

-6x +2/23 =2
Solve the equation

x=-22/69
The possible solution of the system is the ordered pair

(x,y)=(-22/69, 2/23)
Check the solution

2/23=3x(-22/69)+12x 2/23=6x(-22/69)+2
Simplify

2/23=2/23=2/23
The ordered pair is a solution

Solution
(x,y)=(-22/69 , 2/23)

4 0

3 years ago