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klio [65]
3 years ago
10

What is the value of the expression below? –50 + 51

Mathematics
2 answers:
Alex Ar [27]3 years ago
7 0
The answer is 1, if you have -50 of something and then add 51 to it, you have 50 to cover it and 1 extra.
kobusy [5.1K]3 years ago
6 0

Answer: it 1 50 minus 51 is 1

Step-by-step explanation:

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Can somebody help me with my spring break packet???
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The answers:
______________________________________________
Problem #1)  Answer choice:  [A]:  " 3 ¾ yd. " .
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Problem #2)  The answer is:  " ⁵⁄₂ m " .
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Explanations follows:
____________________________________________
Problem #1) 
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A = L * w;

Given:  A = 5 ⅝ yd² ;
            L  = 1<span>½ yd ; 
</span>________________________
Find:  "w" ; 
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Since: A = L * w ; rearrange the equation to isolate "w" on one side of the equation; then plug in our known values to solve for "w"; 
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 Since:  "A = L * w" ;   Divide EACH SIDE of the equation by "L" ;
to isolate "w" on one side of the equation:
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      A / L  = (L * w) / L ;      A / L = w ;

↔ w  = A / L  = (5 ⅝ yd²) / (1½ yd) = (5.625 yd²) / (1.5 yd) = 3.75 ;

w = 3.75 yd. ; which equals:  3 <span>¾ yd. ; which is: "Answer choice: [A]".
</span>_________________________________________________
Problem #2)
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A = L * w;

Given:  A = (35/4) m² ;
            L  = (7/2) m ; 
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Find:  "w" ; 
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Since: A = L * w ; rearrange the equation to isolate "w" on one side of the equation; then plug in our known values to solve for "w"; 
_________________________________________________
 Since:  "A = L * w" ;   Divide EACH SIDE of the equation by "L" ;
to isolate "w" on one side of the equation:
_________________________________________________
      A / L  = (L * w) / L ;      A / L = w ;

↔ w  = A / L  = [(35/4) m²)] / [(7/2) m] =
 
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_______________________________________________
                                                           =  </span>⁵⁄₂ <span>m ;
           {since the problem specifically asks to keep the 'fraction form"}.</span>
______________________________________________________
6 0
3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Ayuda
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