It is 1.86
hope it helps!!
cupcake~
6 x (-3) = -18
6 + (-3) = 3
The numbers are 6 and -3
a. Find the probability that an individual distance is
greater than 214.30 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (214.30 – 205) / 8.3
z = 1.12
Since we are looking for x > 214.30 cm, we use the
right tailed test to find for P at z = 1.12 from the tables:
P = 0.1314
b. Find the probability that the mean for 20 randomly
selected distances is greater than 202.80 cm
We find for the value of z score using the formula:
z = (x – u) / s
z = (202.80 – 205) / 8.3
z = -0.265
Since we are looking for x > 202.80 cm, we use the
right tailed test to find for P at z = -0.265 from the tables:
P = 0.6045
c. Why can the normal distribution be used in part (b),
even though the sample size does not exceed 30?
I believe this is because we are given the population
standard deviation sigma rather than the sample standard deviation. So we can
use the z test.
Answer:
Step-by-step explanation:
Not likely (less than 50 %)
Answer:
x = 600 pages
Step-by-step explanation:
Let the total books pages be x
Given that
Hank had read = 25% of x
25% of x = 150
=>
Multiplying both sides by 4
=> x = 150 * 4
=> x = 600 pages
Step-by-step explanation:
There you go.
