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lyudmila [28]
3 years ago
10

Jordan can make 5 bracelets in 2 hours . At this rate , how long will Jordan take to make 20 bracelets?

Mathematics
2 answers:
Keith_Richards [23]3 years ago
5 0
If she can make 5 in 2 hours, than just multiply 5X4 to get 20 which lets you know to also multiply 2 by 4. 

answer; jordan can make 20 bracelets in 8 hours
finlep [7]3 years ago
4 0
8 hours

5 | 2
20 | x

20/5= 4
2x4= 8
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For any integers x and y, min(x, y) and max(x, y) denote the minimum and the maximum of x and y, respectively. For example, min(
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Answer:

min(10,w)=\left \{ {{w} \quad\text{for } w

Step-by-step explanation:

No value of w is given, so we can only tell you the meaning of <em>min(10, w)</em>:

When w < 10, min(10, w) is w.

When w ≥ 10, 10 is the smaller of the two values, so min(10, w) = 10.

3 0
3 years ago
Billy is hiking in Colorado. He walks eastward four miles, then turns $60$ degrees northward and walks six miles. How far is he
nikklg [1K]

He is  2√19 miles far way from starting point.

Suppose Billy starts at point A, turns at point B, and ends at point D, as shown below.

If Billy turns 60◦ northward and walks six miles, then we can draw a 30 − 60 − 90 triangle whose hypotenuse is 6 miles

It follows that Billy traveled 6/2 = 3 miles eastward during these 6 miles, and that he traveled 3√3 miles northward during these 6 miles. In total, Billy traveled 4 + 3 = 7 miles  eastward and 3√ 3 miles northward.

By the Pythagorean Theorem, the distance from his starting point is q:

(7)2 + (3√3)2

=√49 + 27

= √76

= 2√19 .

Learn more about Pythagorean Theorem on:

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5 0
1 year ago
I need the answer ...
solong [7]
Ooh so the directions tell us what we need to find the entire line, which is made up of FH. so just add GH (15) and FG (6) together to find FH. so that is 21. FH=21.
3 0
3 years ago
he table below shows 10 data values: What values of minimum, Q1, median, Q3, and maximum should be used to make a box plot for t
SVETLANKA909090 [29]
From the given data sets we shall obtain the answers as follows:
<span>301 345 305 394 328 317 361 325 310 362
Re-arrange the data in ascending order:
301, 305, 310, 317,325, 328, 345, 361, 362, 394
from the above we see that:

Minimum value=301

Q1=310

median=(325+328)/2=326.5

Q3=361

Maximum value=394

Thus the box plot will be as follows:

</span>

7 0
2 years ago
Read 2 more answers
This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out
Dmitry [639]
  • Base be y

ATQ

\\ \sf\longmapsto xy=6050\dots 1

\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2

Now

\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy

\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2

\\ \sf\longmapsto 12100-12100=x^2+y^2

\\ \sf\longmapsto x^2+y^2=0\dots(3)

From all equations

\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy

\\ \sf\longmapsto (x-y)^2=0-2(6050)

\\ \sf\longmapsto (x-y)^2=-12100

\\ \sf\longmapsto (x-y)=110\dots(4)

Now

Adding 3 and 4

\\ \sf\longmapsto 2x=220

\\ \sf\longmapsto x=110m

One side won't be covered hence

  • y=2(110)=220m
7 0
2 years ago
Read 2 more answers
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