Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
It is C.
1 times 48 is 48.
2 times 24 is 48
3 times 16 is 48
4 times 12 is 48
6 times 8 is 38.
Answer:
5. The initial value corresponds to the y value when x = 0.
Step-by-step explanation:
You are given the graph, so you do not need to plot anything. Finding rise over run does nothing to help you find the initial value.
The "initial value" on a graph of a linear function is also known as the "y-intercept." It is the y-value corresponding to x = 0.
I believe you are expected to simplify. To do this all you do is group like terms (x, x², x³ etc.) and then simplify the coefficients.
13. 10z + 7z - 19z² - 5z² - 17z
first you can rearrange and group like terms (remember the bring the sign in front of each term with it). I would do it like this:
-19z² - 5z² +10z + 7z - 17z
Now simplify the coefficients:
-24z² + 0z
you can omit the 0z and your simplified answer is
-24z²
Main thing to remember here is that z and z² cannot be simplified together, nor can any variable that has an exponent because the exponent makes them differ.
Answer:
A. The Number of Lost games = 154 Games
B. Number of games won is greater than the number of games lost.
Step-by-step explanation:
A. how many games did they lose in both years?
Total Number of games = 104 tournaments x 3 Games in each tournament
Total Number of games = 312 Games
The No. of Lost games= Total Games in 2 years - Games won in 1st year - Games won in 2nd year
The No. of Lost games = 312 - 55 - 103
The No. of Lost games = 154 Games
B. Is the number of games won greater than the number of games lost?
Total Number of Games won = 158 Games
Total Number of Games lost = 154 Games
Hence, Total Number of Games won is greater than the Total Number of Games lost.
