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Solve: 3/K+3 = 8/k-2
1 answer:
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Answer:
The age of brothers are 4 years and 2 years respectively.
Step-by-step explanation:
We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.
Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.
So, according to the question;
- The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;
-------------- [equation 1]
- The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;
= 2 years
Putting the value of y in equation 1 we get;
x = 2y
x = = 4 years
Hence, the age of brothers are 4 years and 2 years respectively.
Answer:
5140 and 3140
Step-by-step explanation:
Note there is a common difference d between consecutive terms in the sequence, that is
d = 140 - 40 = 240 - 140 = 340 - 240 = 100
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 40 and d = 100, thus
= 40 + (51 × 100) = 40 + 5100 = 5140
= 40 + (31 × 100) = 40 + 3100 = 3140