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murzikaleks [220]
3 years ago
7

Solve for x. Show your work. -1/2x <-12

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
8 0

Answer:

24

Step-by-step explanation:

Multiply both sides of the inequality by -2 qnd flip the inequality sign:

- 2 \times ( -  \frac{1}{2} )x >  - 2x( - 12)

Multiply an even number of negative terms make the product positive:

2 \times  \frac{1}{2} x >  -2 \times ( - 12)

Reduce the number with the greatest common factor 2:

x >  - 2 \times ( - 12)

Multiply two negatives equal a positive: ( - ) × ( - ) = ( + ).

Multiply the number:

x > 2 \times 12

= 24

vitfil [10]3 years ago
5 0

Answer:

x>24

Step-by-step explanation:

First, let's re-write it multiplied by -2 on each side, the denominator will disappear and we'll have our x positive:

x>24

Remember: if you multiply a inequality for a negative number, change the sign to its opposite, for example the < become the >

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Solve for y hdgkgsydkydutskgxtisit
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Multiply each side by (y-2):

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Add  2X  to each side:

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Divide each side by  (X-5):

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7 0
3 years ago
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Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
miskamm [114]

Answer:

  114°

Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

  5x = 45 . . . . . . . . . divide by °, subtract 15+6x

  x = 9 . . . . . . . . . . divide by 5

The measure of exterior angle KMN is ...

  m∠KMN = (11(9) +15)° = 114°

_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

  60° +6x° +M = 180°

  (11x +15)° +M = 180°

Equating these expressions for 180° and subtracting M gives the relation we used above:

  (11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°

  (11x +15)° = 60° +6x° . . . . . . . . . . . subtract M

This is also described by "supplements to the same angle are equal."

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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25.75-5.15=20.60

6 0
3 years ago
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Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17
rodikova [14]
The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW²   → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW²  → (2)
From (1) , (2)  ⇒⇒⇒ ∴ WA = WB  →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW²   → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW²  → (5)
From (4) , (5)  ⇒⇒⇒ ∴ WC = WB  →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17

The correct answer is option D. WB = 17






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