Answer:
Explained below.
Step-by-step explanation:
Consider the series is a set of first 6 natural numbers.
Sum of first <em>n</em> terms is:
Consider the series is an arithmetic sequence.
Sum of first <em>n</em> terms is:
![S_{n}=\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
Here<em>,</em>
<em>a</em> = first term
<em>d</em> = common difference
Consider the series is an geometric sequence.
Sum of first <em>n</em> terms is:
Here<em>,</em>
<em>a₁</em> = first term
<em>r</em> = common ratio
Note: The third term of the sequence should be 
instead of 
, otherwise the sequence has no common ratio.
Given:
The given sequence is
To find:
The common ratio of the given sequence.
Solution:
The quotient of each pair of consecutive terms are:
Similarly,
And,
Therefore, the common ratio of the given sequence is 
or 0.75.
Answer:
fakejjajanKsksns znzmsmmsskskkkkksksjzbzhz
There are 3 different numbers
slot method
how many 3 digit numbers?
321
312
123
132
213
231
6 numbes
how many 2 digit numbers?
12
21
13
31
23
32
6 numbers
how many 1 digit numbers
1
2
3
3 of them
6+6+3=15
15 different number, yah you ar right
