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3 years ago

Which formula do you need to convert 77º F into kelvins?

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

K = (y °F – 32) ÷ 1.8 + 273.15 or K = (y °F – 32) x 5/9 + 273.15

maks197457 [2]3 years ago

3 0

first subtract 273.15 then multiply by 1.8 and add 32

so (77-273.15)x1.8+32

(-196.15) x 1.8 + 32

-353.07 + 32

-321.07

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3 years ago

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3 years ago

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I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Step2247 [10]

Answer:

$A = 297\pi$

Step-by-step explanation:

To solve this problem we need to be familiar with the formula for the surface area of a cone:

$A = \pi r(r + \sqrt{h^2+r^2})$

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

$r = \frac{d}{2}\\r = \frac{18}{2}\\r = 9 cm$

To calculate the height of the cone, we must use the Pythagorean Theorem:

$C^2 = A^2 + B^2$

We can treat the side length as the hypotenuse $C$ , the radius as the base $A$ , and solve for height $B$ . Set the expression up like this:

$C^2 = A^2 + B^2\\24^2 = 9^2 + B^2\\B^2 = 24^2 - 9^2\\B = \sqrt{24^2 - 9^2}\\B = \sqrt{576 - 81}\\B = \sqrt{495}\\B \approx 22.25$

Now we can plug into our original formula:

$A = \pi r(r + \sqrt{h^2+r^2})\\A = \pi 9(9+\sqrt{\sqrt{495}^2+9^2}\\A = \pi 9(9+\sqrt{495 + 81}\\A = \pi 9(9+\sqrt{576})\\A = \pi 9(9 + 24)\\A = \pi 9(33)\\A = 297\pi$

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2 years ago

Roberto has a sample of an unknown liquid. The label in the bottle of the sample indicates that the liquid has a mass of 117 gra

Tomtit [17]

Answer:

It is Milk

Step-by-step explanation:

The liquid in the bottle has mass given in grams and the mass of that substance is 117 grams.

The volume of the substance is 15 cubic centimeters.

Now, using the formula of density we can estimate which substance could it be.

$d=\frac{m}{v}$ , where 'd', is the density, 'm' is the mass, and 'v' is the volume of the substance.

Plugging the value of mass and volume we get:

$d=\frac{117}{15} =7.8g/cm^3$

So the density of the substance is 7.8 grams per cubic centimeter.

It cannot be water since the density of water is 1 grams per cubic centimeter.

It cannot be gasoline because its density is 0.77 grams per cubic centimeter.

It cannot be mercury because the density of mercury is 13.56 grams per cubic centimeter.

Since, the density in this case matches the density of thick milk and hence,therefore, the liquid in the bottle is milk.

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3 years ago