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san4es73 [151]
3 years ago
11

Bradley wanted a blue gumball and a green gumball from a vending machine. There were 15 blue gumballs, 12 yellow gumballs, 2 gre

en gumballs, and 16 purple gumballs. How many times would you expect to get a blue gumball or green gumball if a gumball was taken out 250 times?
Mathematics
1 answer:
jeka943 years ago
3 0

Answer: Bradley would expect 94 times to get a blue or green gumball.

Step-by-step explanation:

Since we have given that

Number of blue gumballs = 15

Number of yellow gumballs = 12

Number of green gumballs = 2

Number of purple gumballs = 16

Total number of all gumballs = 45

Probability of getting either a blue gumball or green gumball be

\frac{15}{45}+\frac{2}{45}=\frac{17}{45}

So, Expectation of getting a blue gumball or green gumball if a gumball was taken out 250 times :

\frac{17}{45}\times 250=94.4

Since we know that it must be less than 94.4.

So, the nearest smallest integer will be 94 times .

Hence, Bradley would expect 94 times to get a blue or green gumball.

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There are 4 cheetahs. There are 3 times as many elephants than cheetahs. Multiply:

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I just need help cause if I don’t I don’t know what imma do
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Answer:

P(32) = \frac{1}{90}

P(Odd) = \frac{1}{2}

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Step-by-step explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

n = 99 - 10 + 1

n = 90

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

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P(32) = \frac{1}{90}

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P(Odd) = \frac{1}{2}

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

P(Multiples\ 5) = \frac{18}{90}

P(Multiples\ 5) = \frac{1}{5}

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Read 2 more answers
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