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4 years ago

Math multiple choice help please

Mathematics

1 answer:

Minchanka [31]4 years ago

3 0

=3k(2k²)-3k(3k)-3k(5)+4(2k²)-4(3k)-4(5)

=6k³-9k²-15k+8k²-12k-20

=6k³-k²-27k-20

....

Break it up into four individual rectangles' areas.

Two have length of x and width of 1, two have length of x-2 (because those 1 width/length squares in the corners are covered by the full length rectangles) and width of 1.

So total area

=x•1+x•1+(x-2)1+(x-2)1

=x+x+x-2+x-2

=4x-4

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