The domain and the range of $g(x) = 9x^2 - 2$ is $(-\infty, \infty)$ .
The parent function $f(x) =x^2$ is vertically compressed by 9, then shifted down by 5 units to get $g(x) = 9x^2 - 2$

Given

$g(x) = 9x^2 - 2$

Domain and range

There is no restriction as to the input and the output of function g(x).

This means that the domain and the range are $(-\infty, \infty)$

$(-\infty, \infty)$ is in interval notation

The corresponding set notation is: $- \infty < x < \infty$

The parent function

We have:

$f(x) = x^2$

First, the parent function is vertically compressed by a factor of 9.

The rule of this transformation is:

$(x,y) \to (x,9y)$

So, we have:

$f'(x) = 9x^2$

Next, the function is shifted down by 5 units.

So, we have:

$g(x) = f'(x) - 5$

$g(x) = 9x^2 - 5$

Read more about functions at:

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An employee at a pet shop randomly selects two fishes from a tank where there are 5 guppies, 4 platyfishes, and 3 rasboras. What

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I believe that it is 0.6.

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Read 2 more answers

A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is

kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

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Point C is in the interior of

PolarNik [594]

Answer:

Point C is in the interior of angle ABD.

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