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Zinaida [17]
3 years ago
5

What is 2.01 times ten to the fifth power into standard form

Mathematics
1 answer:
disa [49]3 years ago
5 0

   Since, you're moving up in exponents, you will move right the number of decimal spaces equivalent to the power of the exponent. Hence, move the decimal point five spaces to the right. There, you now have your answer. :)

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Which are solutions of x2=-11+4?
Dovator [93]

For this case we have a quadratic equation of the form:

ax ^ 2 + bx + c = 0\\x ^ 2 + 11x-4 = 0

Where:

a = 1\\b = 11\\c = -4

We find the roots:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}\\x = \frac {-11 \pm \sqrt {11 ^ 2-4 (1) (- 4)}} {2 (1)}\\x = \frac {-11 \pm \sqrt {121 + 16}} {2}\\x = \frac {-11 \pm \sqrt {137}} {2}

The roots are:

x_ {1} = \frac {-11+ \sqrt {137}} {2}\\x_ {2} = \frac {-11- \sqrt {137}} {2}

Answer:

x_ {1} = \frac {-11+ \sqrt {137}} {2}\\x_ {2} = \frac {-11- \sqrt {137}} {2}

3 0
3 years ago
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solniwko [45]
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JulsSmile [24]

Answer:

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Answer:

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Step-by-step explanation:

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Can you help explain how to get the answer in this question?
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