What is f(1) given f(x)=2|x|+3x

Charlie is charging his tablet. The graph shows how long it takes for his tablet to charge. Use the graph to answer Parts A-D.

almond37 [142]

I just got kicked out of the game and I got kicked out of

4 0

3 years ago

A line passes through the point (-4, -2) and has a slope of -5/2. Write an equation in slope- intercept form for this line.

kirill115 [55]

Answer:

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -⁵/₂

(-4, -2) ⇒ x₀ = -4, y₀ = -2

The point-slope form of the equation:

y + 2 = -⁵/₂(x + 4)

So:

y + 2 = -⁵/₂x - 10 {subtract 2 from both sides}

y = -⁵/₂x - 12 ← the slope-intercept form of the equation

5 0

3 years ago

A rock is thrown upwards from the top of a building 200 feet high with an initial velocity of 96 feet per second

dmitriy555 [2]

T=3-√ 43/2=-1.63 and 3+√ 43/2=7.63

and since time can't be negative, it hits the ground at 7.63 seconds.

and then for 3 there are two steps. Use t=−b2a to find the time of max height. Then plug that time into the h(t) equation

the same values you used in the quadratic equation a = -16, b = 96, c = 200

t=−962(−16)

344 is the answer.

6 0

3 years ago

What is true about the solution above.

Masja [62]

ANSWER

$x = \pm \sqrt{3}$

and they are actual solutions.

EXPLANATION

The given equation is:

$\frac{ {x}^{2} }{2x - 6} = \frac{9}{6x - 18}$

Cross multiply

${x}^{2} (6x - 18) = 9(2x -6 )$

This implies;

${x}^{2} (6x - 18) - 9(2x - 6) = 0$

$3{x}^{2} (2x - 6) - 9(2x - 6) = 0$

Factor

$(3 {x}^{2} - 9)(2x - 6) = 0$

$3 {x}^{2} - 9 = 0 \: or \: 2x - 6= 0$

$3 {x}^{2} = 9 \: or \: 2x = 6$

${x}^{2} = 3\: or \: x = 3$

${x} = \pm \sqrt{3} \: or \: x = 3$

The domain of the given equation is

$x \ne3$

Therefore the actual solutions are

$x = \pm \sqrt{3}$

NB: x=3 is not in the domain of the given equation. It cannot be an extraneous solution.

7 0

3 years ago

Would anyone help With these questions it's the last one I don't know how to do them 1,2,3,4,5 and 6

Shtirlitz [24]

Answer:

See below

Step-by-step explanation:

1. Use x to designate the number of hours worked.

Plumber 1 = 35(x) + 25

Plumber 2 = 40(x)

Now you need to find when these two equations are equal to each other.

35(x) + 25 = 40(x)

Solve for x.

25 = 40x - 35x

25 = 5x

5 = x

So when the service call equals 5 hours, both plumbers will charge the same amount of money.

2. Use x to designate the number of months.

Center 1 = 30x

Center 2 = 22x + 80 initiation fee

Now you need to make the two equations equal to each other and solve for x.

30x = 22x + 80

30x - 22x = 80 or 8x = 80

x = 10 months

3. Use x to designate the pounds of the package

Shipper 1 = 14 + 2x

Shipper 2 = 20 + 1.5x

Make the two equations equal to each other.

14 + 2x = 20 + 1.5x

2x - 1.5x = 20 - 14

0.5x = 6

x = 12 pounds

4. Deanna $15 using $0.75 per game. This means she can play a total of 20 games before having $0.

Lise $13 using $0.50 per game. This means she can play a total of 26 games before having $0.

So since both end up with $0, you can see that Deanna would play 20 games and Lise would play 26 games.

5. Use x to designate the call time length.

Hotel 1 = 1 + 0.80x

Hotel 2 = 2 + 0.75x

Make both equations equal to each other.

1 + 0.8x = 2 + 0.75x

0.8x - 0.75x = 2 - 1

0.05x = 1

x = 20

6. Use x to designate semesters.

Duke = 22 + 6x

Kila = 4 + 12x

22 + 6x = 4 + 12x

22 - 4 = 12x - 6x

18 = 6x

3 = x semesters

6 0

3 years ago