Question

A rock is thrown upwards from the top of a building 200 feet high with an initial velocity of 96 feet per second

Answer 1

T=3-√ 43/2=-1.63 and 3+√ 43/2=7.63

and since time can't be negative, it hits the ground at 7.63 seconds.

 and then for 3 there are two steps. Use t=−b2a to find the time of max height. Then plug that time into the h(t) equation

the same values you used in the quadratic equation a = -16, b = 96, c = 200

t=−962(−16)

344 is the answer.