Answer:
C. 85 degrees
Step-by-step explanation:
Step 1: Set up equation
x + 57 + 96 + x = 131
Step 2: Solve for <em>x</em>
2x + 153 = 131
2x = -22
x = -11
Step 3: Find m∠RQU
m∠RQU = 96 + <em>x</em>
m∠RQU = 96 - 11
m∠RQU = 85°
Answer: 7
Step-by-step explanation:
1. multiply both sides by -6 so the -6 on the right side could cancel out and the left side would be -6: 1= a-13/-6 ==> -6=a-13
2. add both sides by 13 so -13 on the right side could cancel out and the left side would be -6+13: -6=a-13 ==> -6+13=a-13+13
3. you know -6+13 equals 7 right? so the answer is a=7
Answer:
Step-by-step explanation:
Given that
sample size n = 55: x bar = 654.16 and s = sample sd = 162.34
Std error = 162.34/sqrt 55 = 21.889
For 95% CI we can use t critical value as population std dev is not known.
df = 54
t critical = 2.004
Margin of error = 2.004 *21.889 = 43.866
Confidence interval lower bound = 654.16-43.866 =610.294
Upper bound = 654.16+43.866=698.026
Confidence interval rounded off at 95% = (610.29, 698.23)
It is 84. multply 10 and 5, then add the rest. hope i could help!
Given a solution

, we can attempt to find a solution of the form

. We have derivatives



Substituting into the ODE, we get


Setting

, we end up with the linear ODE

Multiplying both sides by

, we have

and noting that
![\dfrac{\mathrm d}{\mathrm dx}\left[x(\ln x)^2\right]=(\ln x)^2+\dfrac{2x\ln x}x=(\ln x)^2+2\ln x](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5Bx%28%5Cln%20x%29%5E2%5Cright%5D%3D%28%5Cln%20x%29%5E2%2B%5Cdfrac%7B2x%5Cln%20x%7Dx%3D%28%5Cln%20x%29%5E2%2B2%5Cln%20x)
we can write the ODE as
![\dfrac{\mathrm d}{\mathrm dx}\left[wx(\ln x)^2\right]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5Bwx%28%5Cln%20x%29%5E2%5Cright%5D%3D0)
Integrating both sides with respect to

, we get


Now solve for

:


So you have

and given that

, the second term in

is already taken into account in the solution set, which means that

, i.e. any constant solution is in the solution set.