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2 years ago

5

Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r

oots does the polynomial have?

1 answer:

Rainbow [258]2 years ago

8 0

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>

Since the degree of given polynomial is 4
Therefore it must have four roots.
Already given that the given polynomial has 1 positive real root and 1 negative real root .
Every polynomial with degree greater than 1 has atleast one imaginary root.

<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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2 years ago

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3 years ago

“Solve each inequality and graph its solution. Show work.”

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Answer:

$p$ or $p >6$

Step-by-step explanation:

Given

$|-5-p| > 11$

Required

Solve and graph

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2 years ago

Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}

Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3> </h3>

To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by $\large \sf a^{n}.$ The terms of a power are:

<h3> </h3>

Base
Exponent
equal factors
power

<h3> </h3>

✏️ <u>Resolution/Answer</u>:

$\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\$

Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

$\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\$

<em>Multiply </em>the power at denominator of the fraction:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\$

<em>Multiply </em>the numerator numbers together:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=$

$\large \sf \dfrac{-16\cdot16\cdot 256 }{16}=$

$\large \sf \dfrac{-256\cdot 256 }{16}=$

$\large \sf \dfrac{- 65536 }{16}=\\\\$

Simplify the fraction by number 16:

$\\\large \sf \dfrac{- 65536 }{16}=$

$\large \sf \dfrac{- 65536 \div16}{16\div16}=$

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}} \\\\\\$

So this expression in its simplified form = -4096/1 or -4096.

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}}\\\\$

★ Hope this helps! ❤️

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2 years ago