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Crank
3 years ago
11

solve this problem by using a 5d process or writing and solving an equation. No matter which method you use, be sure to define y

our variable and write an equation to represent the relationship A rectangle has a perimeter of 30 inches. its length is one less than three times its width what are the length and wodyh of the rectangle?
Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0

Answer:

width of the rectangle=x=4in and length of the rectangle=11in

Step-by-step explanation:

Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.

Now, width=b=x and length=l=3x-1, thus

Perimeter of the rectangle= 2(l+b)

⇒30=2(3x-1+x)

⇒15=(3x-1+x)

⇒15=4x-1

⇒16=4x

⇒x=4in

Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.

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Solve for d 2 + d = 2 - 3 (d - 5) -2
Kobotan [32]

Answer:

3.25

Step-by-step explanation:

2 + d = 2 - 3 (d - 5) -2

d= -3d+15-2

4d=13

d= 13/4= 3.25

5 0
3 years ago
Read 2 more answers
An example problem in a Statistics textbook asked to find the probability of dying when making a skydiving jump.
MArishka [77]

Answer:

(a) 0.999664

(b) 15052

Step-by-step explanation:

From the given data of recent years,  there were about 3,000,000 skydiving jumps and 21 of them resulted in deaths.

So, the probability of death is \frac{21}{3000000}==0.000007.

Assuming, this probability holds true for each skydiving and does not change in the present time.

So, as every skydiving is an independent event having a fixed probability of dying and there are only two possibilities, the diver will either die or survive, so, all skydiving can be regarded as is Bernoulli's trial.

Denoting the probability of dying in a single jump by q.

q=7\times 10^{-6}=0.000007.

So, the probability of survive, p=1-q

\Rightarrow p=1-7\times 10^{-6}=0.999993.

(a) The total number of jump he made, n=48

Using Bernoulli's equation, the probability of surviving in exactly 48 jumps (r=48) out of 48 jumps (n=48) is

=\binom(n,r)p^rq^{n-r}

=\binom(48,48)(0.999993)^{48}(0.000007)^{48-48}

=(0.999993)^{48}=0.999664 (approx)

So, the probability of survive in 48 skydiving is 0.999664,

(b) The given probability of surviving =90%=0.9

Let, total n skydiving jumps required to meet the surviving probability of 0.9.

So, By using Bernoulli's equation,

0.9=\binom {n }{r} p^rq^{n-r}

Here, r=n.

\Rightarrow 0.9=\binom{n}{n}p^nq^{n-n}

\Rightarrow 0.9=p^n

\Rightarrow 0.9=(0.999993)^n

\Rightarrow \ln(0.9)=n\ln(0.999993) [ taking \log_e both sides]

\Rightarrow n=\frac {\ln(0.9)}{\ln(0.999993)}

\Rightarrow n=15051.45

The number of diving cant be a fractional value, so bound it to the upper integral value.

Hence, the total number of skydiving required to meet the 90% probability of surviving is 15052.

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3 years ago
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