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kobusy [5.1K]
3 years ago
8

(x-6)^2+(y+5)^2=212 what is the center of the circle?

Mathematics
1 answer:
madam [21]3 years ago
4 0
The circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". 
Therefore the center is: (6,-5)
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Y varies inversely with x and x= 3 when y =10. What is the value of y when x=6?<br> k =<br> y=
iris [78.8K]

Answer: Y=20

Step-by-step explanation:

X is doubled from 3 to 6 meaning that y is also doubled.

Double 10 is 20 so y=20.

7 0
2 years ago
I need help on 11,13,14,15
vlabodo [156]
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6 0
3 years ago
100 points !!!!!!!!!!!!! please help
m_a_m_a [10]

We have to,

write a word problem for this equation,

→ 2/3 × 5

Let's write a word problem,

<u>For one student 2/3 part of one cake is needed. Then how </u><u>many</u><u> </u><u>cakes will they have to buy for 5 students?</u>

5 0
3 years ago
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Doss [256]

Answer:

x=-b/2a

Step-by-step explanation:

hope that helps :)

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8 0
3 years ago
Which of the following is a point-slope equation of a line that passes through
Mademuasel [1]

Answer:

The Answer is: y = -2/3x + 10/3

Step-by-step explanation:

Given points (-1, 4) and (8, -2) first find the slope:

m = (y - y1)/(x - x1)

m = (4 - (-2)) / (-1 - 8)

m = 4 + 2 / -9

m = -6/9 = -2/3

Use the point slope form and point (8, -2) and slove for y:

y - y1 = m(x - x1)

y - (-2) = -2/3(x - 8)

y + 2 = -2/3x + 16/3

y = -2/3x + 16/3 - 2

y = -2/3x + 16/3 - 6/3

y = -2/3x + 10/3

Proof using the point (-1, 4):

f(-1) = -2/3(-1) + 10/3

= 2/3 + 10/3

= 12/3 = 4, giving point (-1, 4)

Hope this helps! Have an Awesome Day!! :-)

4 0
3 years ago
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