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3 years ago

Kai wrote the number 85 on the board is 85 prime or composite?

Mathematics

2 answers:

solong [7]3 years ago

5 0

The answer to is 85 prime or composite is composite

laila [671]3 years ago

4 0

Composite because prime can only be multiplied by itself but 85 can be multiplied by 5

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For a function p(x)= x^2-9, what is the inverse function for the domain [0, infinity\

kkurt [141]

An inverse function is a function that reverses another function, so we have a function called:

$p(x)$

Then, the inverse function will be as follows:

$p^{-1}(x)$

Given that $y = p(x)$ , we need to isolate x in terms of y:

$y = x^{2} -9$
∴ $y+9 = x^{2}$

So:

$x=+\sqrt{y+9}$ and $x=-\sqrt{y+9}$

therefore, exchanging variables x and y:

$y=+\sqrt{x+9}$ and $y=-\sqrt{x+9}$
$p^{-1}(x)=+\sqrt{x+9}$ and $p^{-1}(x)=-\sqrt{x+9}$

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

5x + 10 = 20

Andrei [34K]

To solve for x, we must first isolate the term containing x which in this problem is 5x.

Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.

On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.

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3 years ago

one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt

In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

$\text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A$

⇒ $\text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A$

$= \frac{3-1}{3} A$

$= \frac{2}{3} A$

$\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B$

⇒ $\text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B$

But, Again according to the question,

The total population that claims that they are from A = one half of the total population of A and B.

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B$

⇒ $\frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B$

⇒ $\frac{1}{6} A = \frac{1}{4} B$

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⇒ $\frac{A}{B} =\frac{3}{2}$

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3 years ago

Find the common factor and factor out 9ab^2-3abc

dsp73

Lets go step by step and factor out each as we go

first lets factor out a 3 since 3 is common in 9 and 3

3(3ab^2 - abc)

now lets factor out a since its common in both

3a(3b^2 - bc)

now lets factor out a b since its common in both

3ab(b - c)

we can't factor anything else out so we are done.

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3 years ago