Answer:
2
Step-by-step explanation:
Answer: 1. -84
2. -21
Step-by-step explanation: I think this is right
See the picture below for a way to construct a right triangle that makes that piece the longest side of the triangle your line segment.
With that setup, you can use they Pythagorean Theorem.
![7^2 + 6^2 = c^2](https://tex.z-dn.net/?f=7%5E2%20%2B%206%5E2%20%3D%20c%5E2)
And then solve that for c, keeping in mind c must be positive.
![\begin{aligned}49 + 36 &= c^2\\85 &= c^2\\\sqrt{85} &= c\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D49%20%2B%2036%20%26%3D%20c%5E2%5C%5C85%20%26%3D%20c%5E2%5C%5C%5Csqrt%7B85%7D%20%26%3D%20c%5Cend%7Baligned%7D)
If you want to use the distance formula, that is just the Pythagorean theorem solved for c:
![d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Applying that to your situation
![d = \sqrt{(5-(-2))^2+(-5-1)^2} = \sqrt{(7)^2+(-6)^2} = \sqrt{49+36} = \sqrt{85}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%285-%28-2%29%29%5E2%2B%28-5-1%29%5E2%7D%20%3D%20%5Csqrt%7B%287%29%5E2%2B%28-6%29%5E2%7D%20%3D%20%5Csqrt%7B49%2B36%7D%20%3D%20%5Csqrt%7B85%7D)
Answer:
C
Step-by-step explanation:
They have the same midpoint.
Hope this helps.