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4 years ago

6

Sam has 2/3 of a piece of poster board. He cuts the poster board into 6 equal size pieces. What part of the whole poster board i

s each smaller piece?

1 answer:

Lerok [7]4 years ago

8 0

2/3 divided by 6

2/3 times 1/6

1/9

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Which is the correct answer?

Nadya [2.5K]

Answer:

c is the correct answer

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3 years ago

Read 2 more answers

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

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3 years ago

Describe the similarities and differences between the pair of terms.

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A Cosine ratio is the hypotenuse in a right triangle is always larger than the adjacent side, so for angles greater than zero but less than 90º the cosine ratio will be less than . and the Secant ratio<span> there are three other trigonometric functions you need to know for the Math IIC: cosecant,</span>secant<span>, and cotangent.</span>

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3 years ago

PICTURE INCLUDED!! PLEASE HELP !! WHICH OF THE FOLLOWING EQUATIONS DESCRIBE THE LINE SHOWN BELOW (-1,6) (2,-6)

GalinKa [24]

(-1,6)(2,-6)
slope = (-6 - 6) / (2 - (-1) = -12 / 3 = - 4

y = mx + b
slope(m) = -4
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6 = 4 + b
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ur equation is : y = -4x + 2 <== this is one

(-1,6)
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Buying 25 individual tokens would be $6.25

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3 years ago