The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,
where 
and 
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
the answer is step by step CFE
8.3% is ur answer hope this helps
Answer:
Mistake in Line 2
Step-by-step explanation:
Line 1
7(6) ÷ 5 + 42
Line 2
7(6) ÷ 5 + 16
Line 3
42 ÷ 5 + 16
Line 4
42 ÷ 21
Line 5
2
To simplify any expression we use order of operation
Line 1 is 7(6) ÷ 5 + 42
Order of operation is PEMDAS
First we start with parenthesis
so we multiply 7(6) in line 2
7*6- 42
So Line 2 is 42 ÷ 5 + 42
Hence there is a mistake in Line 2
Perimeter of a square: side length * 4, since squares have equal side lengths
Take 2x - 3 for the side length and plug it into the formula.
(2x - 3) * 4 can be rewritten as 4(2x - 3)
Distribute 4 inside the parentheses.
8x - 12 = perimeter of the square
