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3 years ago

What is the length of a diagonal of a cube with a side length of 1 cm?

Mathematics

1 answer:

AURORKA [14]3 years ago

4 0

The answer is 4 you have to multiply

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You invest $1000 in an account at 2.5% per year simple interest. How much will you have in the account after 3 years? Round to t

denis23 [38]

Interest = Principle * rate * time
I = PRT

P = 1000
R = 2.5% -- change to a decimal = .025
T = 3

 now we sub I = PRT
I = (1000)(.025)(3)
I = 75
so at the end of 3 years, there will be : 1000 + 75 = $ 1075 in the account

6 0

3 years ago

Read 2 more answers

Find the y-intercept of the graph shown. Pls show work!

andreev551 [17]

-4
It is the point where the line touches the y-axis

3 0

3 years ago

The figure shows the dimensions of a room. How much carpet is needed to cover the floor of the room?

Sati [7]

Answer: 24m

Step-by-step explanation:

How much carpet is asking the area and area= LW

so Length(4) x Width(6) = 24

8 0

3 years ago

Read the quotation from "Song of Myself."

maw [93]

Answer:

the answer is A

4 0

3 years ago

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$

7 0

3 years ago