Answer:

Now we are supposed to find probabilities that the response time is between 5 and 10 minutes i.e P(5<x<10)
Formula : 
at x = 5


at x = 10


P(-2<z<0.6315)=P(z<0.6315)-P(z<-2)
Refer the z table
P(-2<z<10)=0.7357-0.0228=0.7129
So, the probability that response time is between 5 and 10 minutes is 0.7129
b)the response time is less than 5 minutes
at x = 5


P(x<5)=P(z<-2)=0.0228
So, the probability that the response time is less than 5 minutes is 0.0228
c)the response time is more than 10 minutes
at x = 10


P(x>10) = 1-P(x<10) = 1-P(z<0.63) = 1-0.7357 = 0.2643
So, The probability that the response time is more than 10 minutes is 0.2643
<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
Raised by $2.25/month
Step-by-step explanation:
9000/1000=9
28-25=3
3*9=27
27/12=$2.25
Answer:
<u>The solutions to this quadratic equation are 10 and 3.</u>
Step-by-step explanation:
1. Let's recall the formula for solving this type of equations, called quadratic equations:
x = ( - b +/- √ b² - 4ac)/ 2a
The equation given is x2 – 13x + 30 = 0,
where a = 1, b = - 13 and c = 30
Now replacing with the real values, we have
x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1
x = [ 13 +/- √ 169 - 120] / 2
x = [13 +/- √ 49]/ 2
x = [ 13 +/- 7 ]/ 2
<u>x₁ = 13 + 7/2 = 20/2 = 10</u>
<u>x₂ = 13 - 7/2 = 6/2 = 3</u>