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Kryger [21]
2 years ago
12

Solve these

}^{2} - 5x + 6" alt=" {x}^{2} - 5x + 6" align="absmiddle" class="latex-formula">
{x}^{2}  - 11x + 28
​
Mathematics
2 answers:
AlekseyPX2 years ago
7 0

Answer:

hope this will help you more

beks73 [17]2 years ago
7 0

Answer:

x^2-5x+6

x = 3, x = 2

x^2-11x+28

x = 7, x = 4

Step-by-step explanation:

One is asked to solve two quadratic equations. Both of these quadratic equations are in standard form. This means that the two equations follow the following general format;

ax^2+bx+c

The quadratic formula is a method of solving a quadratic equation using the coefficients of the terms in the equation. The quadratic equation is the following,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute in each of the terms and solve for the roots in each equation;

x^2-5x+6

Substitute, and solve

\frac{-(-5)(+-)\sqrt{(-5)^2-4(1)(6)}}{2(1)}\\\\=\frac{5(+-)\sqrt{25-25}}{2}

=\frac{5+1}{2}          =\frac{5-1}{2}

=3               =2

x^2-11x+28

Substitute, and solve

\frac{-(-11)(+-)\sqrt{(-11)^2-4(1)(28)}}{2(1)}\\=\frac{11(+-)\sqrt{121-112}}{2}

=\frac{11+\sqrt{9}}{2}           =\frac{11-\sqrt{9}}{2}

=\frac{11+3}{2}              =\frac{11-3}{2}

=7                     =4

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