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3 years ago

What is the formula for the Pythagorean theory?

Mathematics

1 answer:

harina [27]3 years ago

3 0

A^2 + b^2= c^2
(a,b,c are right triangle sides)

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Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min

alina1380 [7]

Answer:

$y=\frac{1}{2}x-2$

Step-by-step explanation:

We have been given two points on a line $(-6,-5)$ and $(-4,-4)$ . We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation $y=mx+b$ , where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

Let point $(-6,-5)=(x_1,y_1)$ and point $(-4,-4)=(x_2,y_2)$ .

$m=\frac{-4-(-5)}{-4-(-6)}$

$m=\frac{-4+5}{-4+6}$

$m=\frac{1}{2}$

Now, we will substitute $m=\frac{1}{2}$ and coordinates of point $(-6,-5)$ in slope-intercept form of equation as:

$-5=\frac{1}{2}*(-6)+b$

$-5=-3+b$

$-5+3=-3+3+b$

$-2=b$

Upon substituting $m=\frac{1}{2}$ and $b=-2$ in slope-intercept form of equation, we will get our required equation as:

$y=\frac{1}{2}x-2$

Therefore, our required equation would be $y=\frac{1}{2}x-2$ .

8 0

3 years ago

ILL BRAINLIEST YOU IF YOU GET IT RIGHT PLEASE HELP

Arada [10]

Answer:

Step-by-step explanation:

I am smart

4 0

3 years ago

Read 2 more answers

Write logb(x/y) as two logs

Makovka662 [10]

Answer:

$log_{b}(x) - log_{b}(y)$

5 0

2 years ago

Divide 6x^2+9x-12/ 3x

uranmaximum [27]

Answer:

2x + 3 - 4/x

Step-by-step explanation:

6x^2 + 9x - 12/ 3x

1. Reduce the expression by cancelling the common factors.

2x^2 + 3x - 4/ x

2. Divide each term in the numerator by the denominator.

2x^2/x + 3x/x - 4/x

3. Simplify each term. Then when you finish to simplify your answwer would be: 2x + 3 - 4/x

i hope its helpful! :D

6 0

3 years ago

Find the value of x and y

Romashka [77]

Step-by-step explanation:

$\triangle ABC \sim\triangle DEF..(Given) \\ \therefore \frac{AB}{DE} =\frac{BC}{EF}=\frac{AC}{DF}..(CSST)\\\\\therefore \frac{6}{4} =\frac{7}{x}=\frac{8}{y}\\\\ \therefore \frac{6}{4} =\frac{7}{x} \\ \therefore \: x = \frac{7 \times 4}{6} \\ \\\therefore \: x = \frac{28}{6} = \frac{14}{3} \\ \\ \huge \red{ \boxed{ \therefore \: x = \frac{14}{3} }} \\ \\ \because \: \frac{6}{4} =\frac{8}{y} \\ \\ \therefore \:y = \frac{4 \times 8}{6} \\ \\ \therefore \:y = \frac{32}{6} \\ \\ \huge \purple{ \boxed{ \therefore \:y = \frac{16}{3} }}\\ \\$

6 0

3 years ago