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brilliants [131]
3 years ago
7

A sociologist wants to know the opinions of employed adult women about government funding for day care. The women were asked to

rate the
government support on a scale of 1 to 5, with a score of 1 representing the least support and a score of 5 representing the highest support. The
probability distribution chart is given.
Rating
Probablity
1 too little 2 helpful but not enough 3 make a difference but insufficent 4 sufficent 5 generous
0.110
0.206
0.464
0.201 0.119
What percentage of women think that the support is sufficient?
A. 0.22
О В.
1.9
OC 20.1
OD
22.0
E.
68.4
Mathematics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

The correct option is C 20.1%.

Step-by-step explanation:

The probability distribution chart representing the opinions of employed adult women about government funding for day care is as follows:

Rating (<em>X</em>)        Probability (<em>p</em>)

     1                      0.110

     2                      0.206

     3                      0.464

     4                      0.201

     5                      0.119

The ratings are defined as follows:

1: too little

2: helpful but not enough

3: make a difference but insufficient

4: sufficient

5: generous

The probability of women who think that the support is sufficient is, 0.201.

The percentage is: 0.201 × 100 = 20.1%

Thus, the percentage of women who think that the support is sufficient is 20.1%.

The correct option is C.

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Answer:

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rewrite

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3 years ago
Suppose that a brand of lightbulb lasts on average 1730 hours with a standard deviation of 257 hours. Assume the life of the lig
Debora [2.8K]

Answer:

P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

Step-by-step explanation:

Normal Distribution

Mean        μ₀  =  1730

Standard Deviation      σ  = 257

We need to calculate  z scores for the values   1689     and      2267

We apply formula for z scores

z =  ( X -  μ₀ ) /σ

X = 1689     then

z = (1689 - 1730)/ 257      ⇒ z = - 41 / 257

z  = -  0.1595

And from z table we get  for  z =  - 0,1595

We have to interpolate

        - 0,15          0,4364

        - 0,16          0,4325

Δ  =   0.01           0.0039

0,1595  -  0,15  =  0.0095

By rule of three

0,01                  0,0039

0,0095                 x ??      x  =  0.0037

And    0,4364  -  0.0037  = 0,4327

Then    P [ X ≤ 1689 ]  =  0.4327     or    P [ X ≤ 1689 ]  = 43,27 %

And for the upper limit  2267  z  score will be

z  =  ( X - 1730 ) / 257       ⇒  z =  537 / 257

z  =  2.0894

Now from z table   we find  for score   2.0894

We interpolate and assume  0.9815

P [ X ≤ 2267 ]  =  0,9815

Ths vale already contains th value of   P [ X ≤ 1689 ]  =  0.4327

Then we subtract  to get    0,9815  -  0,4327   = 0,5488

Finally

P [ 1689  ≤   X  ≤  2267 ]  =  0,5488  or  P [  1689  ≤   X  ≤  2267 ]  = 54,88 %

8 0
3 years ago
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