Answer:
C. 439.6 in.²
Step-by-step explanation:
The container is a cylinder.
Since the two circular bases won't be covered, therefore:
The least construction paper needed to cover the remaining surface = curved surface area of the cylinder
= 2πrh
r = 5 in.
h = 14 in.
Plug in the values
Curved surface area = 2×π×5×14 = 439.6 in.²
The length would be 85 km
We have a decimal system.
After the decimal point starts the negative powers of ten in those columns...
. 10^-1, 10^-2, 10^-3, 10^-4, 10^-5
1/10s, 1/100s, 1/1000s, 1/10,000s, 1/100,000s
so .00463 is equal to
463/100000